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Consider a conducting sphere placed in otherwise uniform electric field. The field
near the sphere gets modified by the charge induced on the sphere. We want to
solve the problem by method of images. For this, consider two charges
and
placed at
and
respectively. The electric field of these
charges at
is
For
,
. Thus, in the limit of
going to infinity with
we have uniform electric field
along z-axis. We compute the effect of the presence of a conducting sphere
of radius
in uniform electric field by computing the electric field of a system
consisting of a conducting sphere of radius
with it's center at the origin and
two charges
and
placed at
and
respectively and
then taking the limit of
with
.
Using method of images, the two image charges are at
and
and their strengths are
and
respectively. Note that we don't need
a charge at the origin as the total image charge is zero. Note that this
configuration of the image charges forms a dipole and in the limit of
the dipole moment is
.
The electric field of the system is then the field due to this dipole, which is placed
at the origin, added to the uniform electric field. We therefore have
 |
|
|
(50) |
The corresponding electric potential is
 |
|
|
(51) |
As expected the potential at the surface of the sphere,
is constant
( zero in this case ). The surface charge density at the surface can be computed
from the normal component of the electric field at the surface of the sphere.
Next: Planar interface of two
Up: Solutions of Poisson's equation
Previous: A point charge in
S.C.Phatak
2007-02-20